Challenge 015

I) double x = 14.7;

int y = x;

System.out.print(y);

An error occurs because we name x a DDT (Double data type) and in the next line, we are switching it to an int value when claiming y = x. In order to fix this, we need to change the second line to double y = x to produce the output of 14.7

II) double x = 14.7;

int y = (int) x;

System.out.print(y);

The output produced is 14. we claim x to be a DDT and then in the next line we are saying make the integer value of y equal to the integer value of x. This is basically truncating the 14.7 to produce 14. The ddt is simply canceled due to (int) x;

III) int x = 14;

double y = x;

System.out.print(y);

This set of statements produces a value of 12.0. Since y = x , then y =14. However, it is calling for a ddt which makes it a double. With a double comes a decimal. A zero is added because we already declared the y = 14 so .0 applied.